Axa Insurance is Hiring Fresh Engineers as Trainees for its Global Technology division

Axa Insurance is hiring fresh engineers as Trainees for its Global Technology division. This is an exciting opportunity for individuals who are looking to start their careers in the field of technology. The role of the Trainee involves coordinating technical development activities across onshore and offshore teams and ensuring that high-quality work products meet the business requirements.

Axa Insurance

The successful candidate will have strong analytical skills and excellent verbal and written communication skills. They should also have moderate fluency in flow charts, basic coding skills in at least one programming language (such as C, C++, Java, or Python), and an understanding of RDBMS/database concepts.

The Trainee will be responsible for estimating work requests, building and maintaining relationships with business teams, participating in knowledge transfer sessions with business teams, and maintaining working relationships with business users, developers, and the application support team. They will report directly to the Technical Lead.

To be considered for this role, candidates must have a Bachelor's degree in the field of computer science. This is an excellent opportunity for individuals who are looking to start their careers in the field of technology and gain hands-on experience working with experienced professionals.

In conclusion, Axa Insurance's Trainee - Global Technology role offers a unique opportunity for fresh engineers to grow their careers and develop their technical skills in a dynamic and supportive environment. With strong analytical skills and excellent communication skills, the successful candidate will have the opportunity to contribute to the success of the Global Technology division.

• Education: B.E / B.Tech /ME/ M Tech / MCA / M.Sc
• Batch: 2023, 2022, 2021
• Experience :  0- 2 Years
• Location: Bangalore
• Skills:- C, C++, Java, Python anyone 
• Apply Link: Click Here 

Wipro is Hiring graduate fresher as Work Integrated Learning Program (WILP)

Wipro is Hiring graduate fresher as Work Integrated Learning Program (WILP)

Wipro Ltd is offering an exciting opportunity for graduate freshers through its Work Integrated Learning Program (WILP) for 2023. This program is aimed at providing hands-on learning experiences to young graduates in the field of Information Technology. The salary offered for the program is INR 15,488.00 per month, with a salary break-up as mentioned.

For the first year, the stipend offered is INR 15,000 plus INR 488 for Employee State Insurance (ESI). The second-year stipend is INR 17,000 plus INR 553 for ESI, while the third-year stipend is INR 19,000 plus INR 618 for ESI. The fourth-year stipend is INR 23,000. Additionally, the program also offers a joining bonus of INR 75,000.

To be eligible for this program, candidates must have passed 10th and 12th standards and must have a graduation degree with 60% or 6.0 CGPA and above as per the university guidelines. The program is open to students who have passed their graduation in the years 2021, 2022, or 2023. The program is open to students who have completed their Bachelor of Computer Application (BCA) or Bachelor of Science (B.Sc) in eligible streams such as Computer Science, Information Technology, Mathematics, Statistics, Electronics, and Physics.

It is important to note that there is a service agreement of 60 months for this program, and candidates are liable to pay back the joining bonus on a pro-rata basis if they decide to leave the organization within this period.

In conclusion, Wipro's Work Integrated Learning Program (WILP) 2023 is a great opportunity for graduate freshers to gain hands-on experience in the field of Information Technology and start their careers with a leading company. With competitive salaries, a joining bonus, and the chance to work with experienced professionals, this is an opportunity that should not be missed.

• Qualification: BCA/BSc  
• Batch: 2021, 2022, 2023
• Percentage Criteria: 60% or 6.0 CGPA and above
• Apply: Click Here
• Last date to Apply: 15 Feb 2023  

Binary search Program in java With Explanation Using Different Ways

 Binary search Program in java

import java.util.Scanner; class BinarySearch { public static void main(String args[]) { int c, first, last, middle, n, search, array[]; Scanner in = new Scanner(System.in); System.out.println("Enter number of elements"); n = in.nextInt(); array = new int[n]; System.out.println("Enter " + n + " integers"); for (c = 0; c < n; c++) array[c] = in.nextInt(); System.out.println("Enter value to find"); search = in.nextInt(); first = 0; last = n - 1; middle = (first + last)/2; while( first <= last ) { if ( array[middle] < search ) first = middle + 1; else if ( array[middle] == search ) { System.out.println(search + " found at location " + (middle + 1) + "."); break; } else last = middle - 1; middle = (first + last)/2; } if ( first > last ) System.out.println(search + " is not present in the list.\n"); } }

public class BinarySearch { public static int binarySearch(int arr[], int x) { int left = 0, right = arr.length - 1; while (left <= right) { int mid = left + (right - left) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] < x) { left = mid + 1; } else { right = mid - 1; } } return -1; } public static void main(String args[]) { int arr[] = { 2, 3, 4, 10, 40 }; int x = 10; int result = binarySearch(arr, x); if (result == -1) { System.out.println("Element not present"); } else { System.out.println("Element found at index " + result); } } }

Explanation:

• The function binarySearch takes an integer array arr and an integer x as input and returns the index of x in arr if it is present. If not, it returns -1.
• The variables left and right are initialized to 0 and arr.length-1, respectively, to represent the lower and upper bounds of the search space.
• In each iteration of the while loop, mid is calculated as the average of left and right.
• If arr[mid] is equal to x, the function returns mid.
• If arr[mid] is less than x, the search space is updated to the right of mid by setting left to mid + 1.
• If arr[mid] is greater than x, the search space is updated to the left of mid by setting right to mid - 1.
• The while loop continues until left is greater than right or x is found. If x is not found, the function returns -1.
• In the main method, the array arr and the search value x are defined, and the result of the binarySearch function is stored in result.
• If result is -1, the program outputs that the element is not present. Otherwise, it outputs the index at which the element was found.
  

Recursive Binary Search Algorithm in Java

 

public int binarySearch(int arr[], int l, int r, int x) { if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) return mid; if (arr[mid] > x) return binarySearch(arr, l, mid - 1, x); return binarySearch(arr, mid + 1, r, x); } return -1; }

 

 Java Stream Binary Search Algorithm

 

public int binarySearch(int arr[], int x) { return IntStream.of(arr).boxed().sorted().collect(Collectors.toList()).indexOf(x); }

Print Prime Number Program in java with Explanation using different ways

 Here are three different ways to print prime numbers in Java:

1)Using a for loop and a nested if statement:

public class Main { public static void main(String[] args) { int n = 100; for (int i = 2; i <= n; i++) { boolean isPrime = true; for (int j = 2; j < i; j++) { if (i % j == 0) { isPrime = false; break; } } if (isPrime) { System.out.print(i + " "); } } } }

Explanation: The outer loop starts from 2 and goes up to n. For each value of i, we use a nested for loop to check if i is divisible by any number between 2 and i-1. If i is divisible by any number, it is not a prime number and we set isPrime to false. If isPrime is still true after the inner loop, we print i as a prime number.

2)Using a for loop and the sqrt function:

public class Main { public static void main(String[] args) { int n = 100; for (int i = 2; i <= n; i++) { boolean isPrime = true; int sqrt = (int) Math.sqrt(i); for (int j = 2; j <= sqrt; j++) { if (i % j == 0) { isPrime = false; break; } } if (isPrime) { System.out.print(i + " "); } } } }

Explanation: This program is similar to the first one, but it uses the Math.sqrt function to find the square root of i. By checking divisibility only up to the square root of i, we can reduce the number of iterations in the inner loop, making the program more efficient.

3) Using the Sieve of Eratosthenes algorithm:

public class Main { public static void main(String[] args) { int n = 100; boolean[] isPrime = new boolean[n + 1]; for (int i = 0; i <= n; i++) { isPrime[i] = true; } for (int p = 2; p * p <= n; p++) { if (isPrime[p]) { for (int i = p * 2; i <= n; i += p) { isPrime[i] = false; } } } for (int i = 2; i <= n; i++) { if (isPrime[i]) { System.out.print(i + " "); } } } }

Explanation: The Sieve of Eratosthenes is a well-known algorithm for finding all prime numbers up to a given limit. The program starts by creating an array of n + 1 boolean values and setting all values to true. Then, it uses two nested for loops to mark all multiples.

How to swap 2 Number without using 3rd variable Program in java with Explanation

Here are three different ways to swap two numbers without using a third variable in Java:

1) Using addition and subtraction:

public class Main { public static void main(String[] args) { int a = 10; int b = 20; a = a + b; // a now contains the sum of a and b, which is 30 b = a - b; // b now contains the original value of a, which is 10 a = a - b; // a now contains the original value of b, which is 20 System.out.println("a = " + a + ", b = " + b); } }

Explanation: By adding a and b, we have the sum of both numbers stored in a. Then, we subtract b from a to get the original value of a stored in b. Finally, we subtract b from an again to get the original value of b stored in a.

2)Using XOR:

public class Main { public static void main(String[] args) { int a = 10; int b = 20; a = a ^ b; // a now contains the bitwise XOR of a and b b = a ^ b; // b now contains the original value of a a = a ^ b; // a now contains the original value of b System.out.println("a = " + a + ", b = " + b); } }

Explanation: The XOR operator ^ returns 1 if either of its operands is 1 but not both, and 0 if both operands are the same. By XORing a and b, we have the bitwise XOR of both numbers stored in a. Then, we XOR a and b again to get the original value of a stored in b. Finally, we XOR a and b one last time to get the original value of b stored in a.

3)Using a temporary variable:

public class Main { public static void main(String[] args) { int a = 10; int b = 20; int temp = a; // store the original value of a in temp a = b; // assign the value of b to a b = temp; // assign the original value of a (stored in temp) to b System.out.println("a = " + a + ", b = " + b); } }

Explanation: By using a temporary variable temp, we can store the original value of a before assigning the value of b to a. Then, we can assign the original value of a (stored in temp) to b, effectively swapping the values of a and b

Sasken is Hiring fresher Engineers for the role of System Software Engineer

Sasken is Hiring fresher Engineers for the role of System Software Engineer

Sasken is currently hiring for the role of System Software Engineer. This position is responsible for applying a broad knowledge of their technical discipline or advanced knowledge of specific technical practices to identify problems in existing systems and modify them by following defined work procedures. The role is operationally oriented and works under the close supervision of the Team Lead or Project Manager.

Sasken Technologies Bangalore

Responsibilities include design, coding, testing, bug fixing, documentation, and technical support in the assigned area. Candidates are expected to adhere to guidelines and checklists for all deliverable reviews, send status reports to the team lead, and follow relevant organizational processes.

The ideal candidate should have a degree in Engineering, MCA, or similar, with 0-2 years of experience. They should be well-versed in a programming language and have done academic projects in the programming language. Candidates should have an understanding of the usage of an IDE for development, basic knowledge of standards, and good problem-solving and reasoning skills to solve basic programming quests and implement data structures and algorithms.

The role requires knowledge of platforms such as Unix, Windows, and Linux (Cent OS or Ubuntu), and technology standards such as Generics. Tools used include IDE's like Eclipse, Visual Studio, Compilers, and Debuggers. Candidates should have knowledge in programming languages such as C, C++, JAVA, PYTHON, KOTLIN, C#, C , C++ , JAVA, PYTHON, KOTLIN, C#.

• Role: System Software Engineer
• Qualification: B.E/B.Tech/MCA 
• Experience: Fresher's to 2 years of exp.
• Apply Link: Click Here 
• Job Location: Bengaluru

Accenture is Hiring freshers Any Graduation role of HR Service Delivery

Accenture is Hiring freshers Any Graduation role in HR Service Delivery

As a fresh graduate in the role of HR Service Delivery at Accenture, you will have the opportunity to work with a team of experienced professionals to provide high-quality HR services to clients. Your primary responsibilities will include analyzing and solving lower-complexity problems, interacting with peers within Accenture, and managing multiple stakeholders.

 Accenture

One of the key skills required for this role is the ability to establish strong client relationships and handle disputes effectively. You will also need to be able to meet deadlines, perform under pressure and handle multiple tasks simultaneously.

In this role, you will be given moderate-level instruction on daily work tasks and detailed instructions on new assignments. The decisions you make will impact your own work and may also impact the work of others. 

As a fresh graduate, this role offers the perfect opportunity to gain experience and develop your skills in a fast-paced and dynamic environment. The role requires strong communication and problem-solving skills, as well as the ability to establish strong client relationships and manage multiple stakeholders.

As an HR Service Delivery professional, you will be responsible for analyzing and solving lower-complexity problems and working closely with your peers within Accenture. You may also have limited exposure to clients and management and will be given moderate-level instruction on daily tasks and detailed instructions on new assignments.

Please note that this role may require you to work in rotational shifts. If you have excellent communication skills, a strong work ethic, and a desire to learn and grow in a dynamic and fast-paced environment, then this may be the perfect opportunity for you. 

• Role: HR Service Delivery
• Job Id: 222620
• Qualification: Any Graduation
• Experience: Freshers to 1 Years of Exp.
• Apply Link: Click Here
• Location: Bangalore